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Answer :
Final answer:
The client will receive 15 mEq (mmol) of potassium per hour if the IV potassium chloride infusion in normal saline is administered at a rate of 150 mL/hour.
Explanation:
The infusion of 100 mEq (mmol) of potassium chloride is spread across 1000 mL of normal saline. To find out how many mEq (mmol) of potassium per hour the client will receive with an infusion rate of 150 mL/hour, you first calculate the concentration of the infusion which is 100 mEq in 1000 mL, simplifying to 0.1 mEq/mL. When the infusion rate is set at 150 mL/hour, the client receives 0.1 mEq/mL * 150 mL which equates to 15 mEq (mmol) of potassium per hour. Therefore, the nurse will calculate that the client is receiving 15 mEq (mmol) of potassium per hour, which corresponds to answer B.) 15 mEq (mmol).
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