We appreciate your visit to The brakes of a car are applied causing it to slow down at a rate of 11 ft s² The car stops at a distance. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The car was traveling at an initial speed of approximately 81.25 ft/s before the brakes were applied, calculated using the kinematic equation for motion with deceleration and distance covered.
Determining Initial Speed Before Braking
- To find the initial speed of the car before the brakes were applied, we'll use one of the kinematic equations of motion. The equation to use is:
v² = u² + 2as
- Where:
- v is the final velocity (0 ft/s, since the car stops).
- u is the initial velocity (what we're trying to find).
- a is the acceleration (-11 ft/s², because the car is decelerating).
- s is the distance (300 ft).
- Rearranging the equation to solve for u:
0 = u² + 2(-11)(300)
0 = u² - 6600
- Therefore:
u² = 6600
- Taking the square root of both sides:
u = √6600 ≈ 81.25 ft/s
So, the initial speed of the car immediately before the brakes were applied was 81.25 ft/s.
Thanks for taking the time to read The brakes of a car are applied causing it to slow down at a rate of 11 ft s² The car stops at a distance. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
The speed of the car immediately before the brakes were applied was 81.24 ft/s.
The given data is given below:
Initial speed = ?
Final speed = 0
Acceleration = -11ft/s²
Time = ?
Distance = 300ft
Using the equation of motion, we have:
final velocity² = initial velocity² + 2 × acceleration × distance
Putting the given values in this formula, we get:
0² = v₀² + 2 × (-11ft/s²) × 300ftv₀²
= 6,600ft²/s²v₀
= √6,600ft²/s²v₀
= 81.24ft/s
Therefore, the speed of the car immediately before the brakes were applied was 81.24 ft/s.
When a car's brakes are applied, it begins to slow down. As a result, it is required to find the initial speed of the car. This issue can be solved using an equation of motion.
Initial velocity, final velocity, acceleration, distance, and time are all variables in the equation of motion. We have the final speed, acceleration, and distance in this problem, and we must determine the initial speed.
We'll substitute the given values into the formula and solve for initial velocity. We can write the equation of motion as follows:
final velocity² = initial velocity² + 2 × acceleration × distance
To calculate the initial velocity of the car, we'll use this formula. We can plug in the final speed as 0, since the car came to a complete stop, and we know that the acceleration was 11ft/s² in the opposite direction of the car's motion because the brakes were applied, and the distance was 300 ft. We obtain the value of initial velocity from this formula.
To know more about speed visit:
https://brainly.com/question/28224010
#SPJ11