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A potential difference of 3.25 nV is set up across a 2.30 cm length of copper wire that has a radius of 2.16 mm. How much charge drifts through a cross section in 3.24 ms? Assume that the resistivity of copper is 1.69 × 10^-8 m.

Answer :

Final answer:

The question is about calculating the amount of charge that drifts through a given length of copper wire under a specific potential difference using physics principles and formulas such as Ohm's Law, resistivity, and the relationship of current and charge.

Explanation:

To work this problem out, we'll use Ohm's Law (V = IR), along with the relationship of current, I, and charge, Q (I = Q/t). We will also use the definition of resistivity (R = ρL/A), where R is the resistance, ρ is the resistivity of copper, L is the length of the wire, and A is the cross-sectional area.

First, solve for the resistance using the given values for ρ, L, and A. Remember that A is calculated given the radius r of the wire using the formula A = πr^2. Once we have the resistance, we can find the current using Ohm’s law (I = V/R).

For the final part, we use the I and given time t to calculate the charge Q with the formula Q = It.

Therefore, by using these formulas we can calculate the amount of charge that drifts through a cross section in a certain amount of time when particular conditions are met.

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