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Answer :
To find the functions that define the graphs after Elena and Han make their adjustments, let's break down what each of them is thinking:
1. Elena's Graph:
Elena wants to shift the graph of the original function [tex]\( f(d) = 25 \times (1.19)^d \)[/tex] up by 50 units.
- Shifting a graph up by a certain number involves adding that number to the function.
- So, to shift the graph of [tex]\( f \)[/tex] up by 50, you would add 50 to the original function.
Therefore, Elena's function becomes:
[tex]\[
g(d) = 50 + 25 \times (1.19)^d
\][/tex]
2. Han's Graph:
Han wants to shift the graph of the original function up by 60 units and then right by 1 unit.
- Shifting the graph up by 60 is similar to Elena's shift, where you add 60 to the function.
- Shifting a graph to the right by 1 unit involves adjusting the input [tex]\( d \)[/tex] by subtracting 1 from it. This means replacing [tex]\( d \)[/tex] with [tex]\( d - 1 \)[/tex] in the function.
Thus, Han's function becomes:
[tex]\[
h(d) = 60 + 25 \times (1.19)^{d-1}
\][/tex]
These transformations result in the functions as described, with [tex]\( g(d) = 50 + 25 \times (1.19)^d \)[/tex] for Elena's adjustments and [tex]\( h(d) = 60 + 25 \times (1.19)^{d-1} \)[/tex] for Han's adjustments.
1. Elena's Graph:
Elena wants to shift the graph of the original function [tex]\( f(d) = 25 \times (1.19)^d \)[/tex] up by 50 units.
- Shifting a graph up by a certain number involves adding that number to the function.
- So, to shift the graph of [tex]\( f \)[/tex] up by 50, you would add 50 to the original function.
Therefore, Elena's function becomes:
[tex]\[
g(d) = 50 + 25 \times (1.19)^d
\][/tex]
2. Han's Graph:
Han wants to shift the graph of the original function up by 60 units and then right by 1 unit.
- Shifting the graph up by 60 is similar to Elena's shift, where you add 60 to the function.
- Shifting a graph to the right by 1 unit involves adjusting the input [tex]\( d \)[/tex] by subtracting 1 from it. This means replacing [tex]\( d \)[/tex] with [tex]\( d - 1 \)[/tex] in the function.
Thus, Han's function becomes:
[tex]\[
h(d) = 60 + 25 \times (1.19)^{d-1}
\][/tex]
These transformations result in the functions as described, with [tex]\( g(d) = 50 + 25 \times (1.19)^d \)[/tex] for Elena's adjustments and [tex]\( h(d) = 60 + 25 \times (1.19)^{d-1} \)[/tex] for Han's adjustments.
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