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Sara has 20 sweets: 12 liquorice sweets, 5 mint sweets, and 3 humbugs.

Sara takes two random sweets.

Work out the probability that the two sweets will not be the same.

Answer :

If sara takes two random sweets. The probability that the two sweets will not be the same is :111/190.

How to find the probability?

Probability of getting two of each sweet:

P( Liquorice) = (12/20)×(11/19)

P (Liquorice) =132/380

P (mints) =(5/20)×(4/19)

P (mints) =20/380

P (Humbugs) =(3/20)×(2/19)

P (Humbugs) =6/380

Probability that two sweets will be the same

P(same) =132/380+20/380+6/380

P(same) =158/380

Hence,

Probability that two sweets will not be the same

P(not same) = 1- (158/380)

P(not same) =380 -158 /380

P(not same) = 222 /380

P(not same) =111 /190

Therefore the probability is 111/190.

Learn more about probability here:https://brainly.com/question/24756209

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