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Answer :
Answer:
Option C [tex]126\ in^{2}[/tex]
Step-by-step explanation:
we know that
The lateral surface area of the cylinder is equal to
[tex]LA=2\pi rh[/tex]
In this problem we have
[tex]r=5/2=2.5\ in[/tex] -----> the radius is half the diameter
[tex]h=8\ in[/tex]
substitute
[tex]LA=2\pi (2.5)(8)=126\ in^{2}[/tex]
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Rewritten by : Barada
By using the formula of lateral surface area of cylinder
A=2πrhwhere
r=2.5 in
h=8 in
putting the values in the given formula :
A= 2x3.14x2.5x8
A=126 in^2
A=2πrhwhere
r=2.5 in
h=8 in
putting the values in the given formula :
A= 2x3.14x2.5x8
A=126 in^2
