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A force of 67 N is applied to a 10-kg object at an angle of 30° with respect to the horizontal table. If the work done on the object is 257 J, how far has it moved in meters (m)? Ignore friction.

Answer :

If A force of 67 N is applied on a 10-kg object at an angle of 30 o with respect to the horizontal table and the work done is 257J then the distance it covered is 3.32 m.

What is force?

A body can change its state of rest or motion through the application of force, which is an external agent. It has both a magnitude and a direction. The application of force is the point at which force is applied, and the direction in which the force is applied is referred to as the direction of the force.

A spring balance can be used to gauge the Force. The SI unit of force is the Newton (N).

The vector product of mass (m) and acceleration (a) is used to express the amount of force (F) . the formula of force can be written like F = m × a.

The formula for work done is

W = fd cos θ

Here force f = 67 N

Work done W = 257 J

θ = 30°

Substituting the values

d = W/F cos θ

d = 257 /67 (cos 30°)

d = 3.32 m

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