You are given a 49 V battery and two resistors of resistances 27.5 Ω and 97.5 Ω.Find the current in A when these resistors are connected in series with the battery.

Question

11-11-2023
Physics

High School

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You are given a 49 V battery and two resistors of resistances 27.5 Ω and 97.5 Ω.Find the current in A when these resistors are connected in series with the battery.

Answer :

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Final answer:

When connected in series, the total resistance is the sum of both resistors' resistances. Using Ohm's law, the current can be found by dividing the voltage by the total resistance. The solution's correctness is confirmed by ensuring the power supplied by the battery equals the power dissipated by the resistors.

Explanation:

The question requires us to calculate the current flowing when a battery and two resistors are connected in series. Here, we are given a battery of voltage 49V and two resistors with resistance 27.5 Ω and 97.5 Ω.

When resistors are connected in series, the total resistance (Rt) is the sum of the individual resistances. Hence, Rt = 27.5 Ω + 97.5 Ω = 125 Ω.

Ohm’s law (V = IR) allows us to calculate the current where V is voltage, I is current and R is resistance. We can find the current (I) by rearranging the formula to I = V/R. So, the current in this circuit would be I = 49V / 125 Ω = 0.392 A or 392 mA.

To validate this, we can apply the power formula (P = V x I). The power supplied by the battery should be equal to the power dissipated by the resistors. Since both values match, this confirms the consistency of our solution.

Learn more about Ohm's Law here:

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