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A black mamba snake has a length of 3.50 m and a top speed of 4.80 m/s. Suppose a mongoose and a black mamba find themselves nose to nose. In an effort to escape, the snake accelerates past the mongoose at 8.06 m/s² from rest.

How much time \(t_{\text{top}}\) does it take the snake to reach its top speed?

Answer :

Final answer:

The snake takes approximately 0.595 seconds to reach its top speed.

Explanation:

To calculate the time it takes for the snake to reach its top speed, we can use the equation of motion:

v = u + at

Where:

In this case, the snake starts from rest, so the initial velocity (u) is 0 m/s. The acceleration (a) is given as 8.06 m/s2. The final velocity (v) is 4.80 m/s, which is the top speed of the snake.

Substituting the values into the equation, we have:

4.80 = 0 + 8.06t

Simplifying the equation, we get:

4.80 = 8.06t

To solve for t, we divide both sides of the equation by 8.06:

t = 4.80 / 8.06

Calculating the value, we find:

t ≈ 0.595 seconds

Learn more about calculating the time it takes for a snake to reach its top speed here:

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