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Answer :
Final answer:
The frequency of the dominant allele (N) in the turtle population is 0.80 when 4% show the recessive phenotype. This is derived by taking the square root of the recessive phenotype frequency to find the recessive allele frequency (q), then subtracting q from 1 to find the dominant allele frequency (p).
Explanation:
The question deals with the frequency of the dominant allele in a turtle population, given that 4% shows the recessive phenotype (long nose). This is a classic problem involving Hardy-Weinberg equilibrium. According to Hardy-Weinberg principles, the frequency of the two alleles in a population can be represented by p and q, where p is the frequency of the dominant allele and q is the frequency of the recessive allele. Since the recessive phenotype frequency is 4% or 0.04, we can denote this as q2 because it is expressed only when the individual has two copies of the recessive allele (nn). We can calculate q by taking the square root of 0.04, which gives us 0.20. The frequencies of p and q must add up to 1, so p = 1 - q, which equals 1 - 0.20, resulting in 0.80. Therefore, the frequency of the dominant allele (N) in the population is 0.80, making option E. 0.80 the correct answer.
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