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Answer :
Final answer:
The atmospheric pressure on the day the temperature increased to 25.9 °C and the new volume was 221.2 mL is approximately 101.5 kPa.
Explanation:
To determine the atmospheric pressure on the day the temperature increased to 25.9 °C and the new volume was 221.2 mL, we can use the combined gas law formula: P1V1 / T1 = P2V2 / T2.
First, convert the temperature to Kelvin: T1 = 15.0 °C + 273.15 = 288.15 K, and T2 = 25.9 °C + 273.15 = 299.05 K.
Now, substitute the values into the formula:
P1 * 225 mL / 288.15 K = P2 * 221.2 mL / 299.05 K.
Solving for P2, the atmospheric pressure on this day is approximately 101.5 kPa.
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