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Answer :
Final answer:
To calculate the volume of one mole of oxygen at 27ºC and 2 atm pressure, use the ideal gas law equation V = (nRT)/P.
Explanation:
To calculate the volume of one mole of oxygen at 27ºC and 2 atm pressure, we can use the ideal gas law equation:
V = (nRT)/P
Where V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), T is the temperature in Kelvin, and P is the pressure.
First, we need to convert the temperature from Celsius to Kelvin. 27ºC + 273.15 = 300.15 K.
Plugging in the values, we have:
V = (1 mol * 0.0821 L·atm/mol·K * 300.15 K) / 2 atm = 12.326 L
Therefore, the volume of one mole of oxygen at 27ºC and 2 atm pressure is approximately 12.326 litres.
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