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Calculate the boiling point (\(^\circ C\)) of an aqueous solution of 2.50 m Fe(NO\(_3\))\(_3\).

\(K_b\) for water is 0.512 \(^\circ C/m\).

Multiple Choice:
A. 101.3 \(^\circ C\)
B. 5.12 \(^\circ C\)
C. 102.5 \(^\circ C\)
D. 2.46 \(^\circ C\)
E. 100.8 \(^\circ C\)
F. 105.1 \(^\circ C\)

Answer :

The boiling point of the aqueous solution of 2.50 m [tex]Fe(NO_3)_3[/tex]is approximately 101.28 °C. So, the correct option nearest to it is B.

We can use the following equation to find the boiling point of an aqueous solution of [tex]Fe(NO_3)_3[/tex]:

Δ[tex]T_b[/tex] = [tex]K_b[/tex] * m

where:

[tex]K_b[/tex] is the molal boiling point elevation constant for water (0.512 °C/m) and [tex]T_b[/tex] is the boiling point elevation

m is the molality of the solute (2.50 m).

Inserting the values:

ΔTb = 0.512 °C/m * 2.50 m

ΔTb = 1.28 °C

The boiling point is calculated by adding the boiling point elevation to the 100 °C boiling point of pure water:

Boiling point = 100 °C + 1.28 °C

Boiling point = 101.28 °C

Hence, the boiling point of the aqueous solution of 2.50 m [tex]Fe(NO_3)_3[/tex]is approximately 101.28 °C.

So, the correct option nearest to it is B.

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