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Answer :
Let the number of pounds of almonds, cashews, and walnuts be [tex]$a$[/tex], [tex]$c$[/tex], and [tex]$w$[/tex], respectively. We are given the following three equations:
[tex]$$
a + c + w = 12 \quad \text{(total pounds)}
$$[/tex]
[tex]$$
7a + 10c + 12w = 118 \quad \text{(total cost)}
$$[/tex]
[tex]$$
w - c = 2 \quad \text{(2 more pounds of walnuts than cashews)}
$$[/tex]
Step 1. Express one variable in terms of another.
From the equation
[tex]$$
w-c=2,
$$[/tex]
we get
[tex]$$
w = c + 2.
$$[/tex]
Step 2. Substitute into the total pounds equation.
Replace [tex]$w$[/tex] in
[tex]$$
a+c+w=12
$$[/tex]
by [tex]$c+2$[/tex] to obtain:
[tex]$$
a + c + (c + 2) = 12 \quad \implies \quad a + 2c + 2 = 12.
$$[/tex]
Subtracting 2 from both sides gives:
[tex]$$
a + 2c = 10 \quad \implies \quad a = 10 - 2c.
$$[/tex]
Step 3. Substitute [tex]$a$[/tex] and [tex]$w$[/tex] into the total cost equation.
Substitute [tex]$a = 10 - 2c$[/tex] and [tex]$w = c+2$[/tex] into
[tex]$$
7a + 10c + 12w = 118:
$$[/tex]
[tex]$$
7(10 - 2c) + 10c + 12(c+2) = 118.
$$[/tex]
Expanding and simplifying:
[tex]$$
70 - 14c + 10c + 12c + 24 = 118.
$$[/tex]
Combine like terms:
[tex]$$
94 + 8c = 118.
$$[/tex]
Subtract 94 from both sides:
[tex]$$
8c = 24 \quad \implies \quad c = 3.
$$[/tex]
Step 4. Solve for [tex]$a$[/tex] and [tex]$w$[/tex].
Now, substitute [tex]$c = 3$[/tex] back into the expressions for [tex]$a$[/tex] and [tex]$w$[/tex]:
[tex]$$
a = 10 - 2(3) = 4,
$$[/tex]
[tex]$$
w = 3 + 2 = 5.
$$[/tex]
Step 5. Interpret the differences.
We now compare the weights:
- The difference between walnuts and almonds is
[tex]$$
w - a = 5 - 4 = 1.
$$[/tex]
- The difference between almonds and cashews is
[tex]$$
a - c = 4 - 3 = 1.
$$[/tex]
Thus, the customer buys 1 more pound of walnuts than almonds and 1 more pound of almonds than cashews.
Final Answer:
The interpretation is:
"The customer buys 1 more pound of walnuts than almonds and 1 more pound of almonds than cashews."
[tex]$$
a + c + w = 12 \quad \text{(total pounds)}
$$[/tex]
[tex]$$
7a + 10c + 12w = 118 \quad \text{(total cost)}
$$[/tex]
[tex]$$
w - c = 2 \quad \text{(2 more pounds of walnuts than cashews)}
$$[/tex]
Step 1. Express one variable in terms of another.
From the equation
[tex]$$
w-c=2,
$$[/tex]
we get
[tex]$$
w = c + 2.
$$[/tex]
Step 2. Substitute into the total pounds equation.
Replace [tex]$w$[/tex] in
[tex]$$
a+c+w=12
$$[/tex]
by [tex]$c+2$[/tex] to obtain:
[tex]$$
a + c + (c + 2) = 12 \quad \implies \quad a + 2c + 2 = 12.
$$[/tex]
Subtracting 2 from both sides gives:
[tex]$$
a + 2c = 10 \quad \implies \quad a = 10 - 2c.
$$[/tex]
Step 3. Substitute [tex]$a$[/tex] and [tex]$w$[/tex] into the total cost equation.
Substitute [tex]$a = 10 - 2c$[/tex] and [tex]$w = c+2$[/tex] into
[tex]$$
7a + 10c + 12w = 118:
$$[/tex]
[tex]$$
7(10 - 2c) + 10c + 12(c+2) = 118.
$$[/tex]
Expanding and simplifying:
[tex]$$
70 - 14c + 10c + 12c + 24 = 118.
$$[/tex]
Combine like terms:
[tex]$$
94 + 8c = 118.
$$[/tex]
Subtract 94 from both sides:
[tex]$$
8c = 24 \quad \implies \quad c = 3.
$$[/tex]
Step 4. Solve for [tex]$a$[/tex] and [tex]$w$[/tex].
Now, substitute [tex]$c = 3$[/tex] back into the expressions for [tex]$a$[/tex] and [tex]$w$[/tex]:
[tex]$$
a = 10 - 2(3) = 4,
$$[/tex]
[tex]$$
w = 3 + 2 = 5.
$$[/tex]
Step 5. Interpret the differences.
We now compare the weights:
- The difference between walnuts and almonds is
[tex]$$
w - a = 5 - 4 = 1.
$$[/tex]
- The difference between almonds and cashews is
[tex]$$
a - c = 4 - 3 = 1.
$$[/tex]
Thus, the customer buys 1 more pound of walnuts than almonds and 1 more pound of almonds than cashews.
Final Answer:
The interpretation is:
"The customer buys 1 more pound of walnuts than almonds and 1 more pound of almonds than cashews."
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