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Answer :
Final answer:
The average speed of the boy during the first 2 minutes and 10 seconds is 3.85 m/s, and his average speed during the entire journey is 3.68 m/s. The magnitude of his average velocity during the initial 2 minutes and 10 seconds is also 3.85 m/s, while during the entire trip, his average velocity is 1.58 m/s.
Explanation:
To calculate the average speed, we divide the total distance covered by the total time taken. In the first 2 minutes and 10 seconds, the boy covered 500m. So, his average speed during this period would be (500 m) / (130 s) = 3.85 m/s.
The magnitude of average velocity during this period is the same as the average speed because he moved in a straight line, which is 3.85 m/s.
For the entire journey, the boy ran a total of 500m towards north and then 200m towards south. So his total distance covered is 500m + 200m = 700m and time taken is 2 minutes 10 seconds + 1 minute = 190 seconds. Hence, average speed for the total journey = Total Distance / Total time = 700m / 190s = 3.68 m/s.
However, for average velocity, we consider the net displacement divided by the total time. The net displacement is the total distance he is away from his starting point which is 500m - 200m = 300m. Hence, the average velocity for the entire journey is 300m / 190s = 1.58 m/s.
Learn more about Average Speed and Velocity here:
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