High School

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The director of health services is concerned about a possible flu outbreak at her college. She surveyed 100 randomly selected residents from the college's dormitories to see whether they had received a preventative flu shot. The results are shown below.

What is the probability that a dormitory resident chosen at random from this group has had a flu shot, given that he is male?

[tex]
\[
\begin{array}{|c|c|c|c|}
\hline
& \text{Male} & \text{Female} & \text{Total} \\
\hline
\text{Had Flu Shot} & 39 & 41 & 80 \\
\hline
\begin{array}{c}
\text{Didn't Have} \\
\text{Flu Shot}
\end{array} & 12 & 8 & 20 \\
\hline
\text{Total} & 51 & 49 & 100 \\
\hline
\end{array}
\]
[/tex]

A. [tex]$\frac{51}{100}$[/tex]

B. [tex]$\frac{39}{80}$[/tex]

C. [tex]$\frac{13}{17}$[/tex]

Answer :

To find the probability that a dormitory resident chosen at random from this group has had a flu shot given that he is male, we need to focus only on the male residents.

Here's how we can determine this probability:

1. Identify the Total Number of Male Residents: From the table, there are a total of 51 male residents.

2. Identify the Number of Male Residents Who Had a Flu Shot: From the table, 39 male residents received a flu shot.

3. Calculate the Conditional Probability: We want to find the probability that a randomly chosen male resident has had a flu shot. The formula for this conditional probability is:

[tex]\[
P(\text{Had Flu Shot | Male}) = \frac{\text{Number of Males Who Had a Flu Shot}}{\text{Total Number of Male Residents}}
\][/tex]

Substituting the numbers we have:

[tex]\[
P(\text{Had Flu Shot | Male}) = \frac{39}{51}
\][/tex]

4. Calculate the Result: When you divide 39 by 51, the result is approximately 0.7647.

Thus, the probability that a randomly selected male dormitory resident has had a flu shot is approximately 0.765, or 76.47%.

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