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When the following code has finished running, what is the value of x?

```c
int x = 100;
int *y = &x;
int *z = &x;
x = 50;
*y = 300;
*z = 50;
```

Answer :

After running the given code, the value of x will be 50.

Let's go through the code step by step:

int x = 100;: This line initializes the variable x with the value 100.

int *y = &x;: This line declares a pointer variable y and assigns it the address of x using the & operator. So y points to the memory location of x.

int *z = &x;: This line declares another pointer variable z and assigns it the address of x using the & operator. So z also points to the memory location of x.

x = 50;: This line directly assigns the value 50 to the variable x. Since y and z are pointers to x, any changes made to x will also reflect through y and z.

*y = 300;: This line dereferences the pointer y using the * operator and assigns the value 300 to the memory location it points to, which is x. Therefore, x now holds the value 300.

*z = 50;: This line dereferences the pointer z using the * operator and assigns the value 50 to the memory location it points to, which is also x. Therefore, x is changed back to 50.

So, at the end of the code, the value of x is 50.

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