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The 5th term of an arithmetic progression (AP) exceeds twice the 2nd term by 1. The 10th term exceeds twice the 4th term by 3.

Find the first term and the common difference of the AP.

Answer :

Final answer:

The problem represents an arithmetic progression. Solving the problem yields the first term (a) as 2 and the common difference (d) as 1.

Explanation:

This problem involves an Arithmetic Progression (AP). In an AP, the difference between any two consecutive terms is constant, known as the 'common difference,' denoted by 'd'. Also, we can denote the first term of the AP as 'a'.

From the first condition, we know that a + 4d = 2(a + d) + 1 which simplifies to 3d = a + 1. From the second condition, we have a + 9d = 2(a + 3d) + 3 which simplifies to 3d = a + 3.

By comparing these two equations, we can see 'a' (first term) is equal to 2, and 'd' (common difference) is equal to 1.

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