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Answer :
Final Answer:
To find the tangent line to the curve at the point (1,1), we first need to differentiate the given function with respect to x, then substitute x = 1 to find the slope of the tangent line. The resulting equation will represent the tangent line.
Explanation:
Given the function (48x⁵ - 60x⁵⁹⁺⁵⁹y) / (x⁶⁰ + 3y⁸), we differentiate it with respect to x using the quotient rule. After differentiation, we substitute x = 1 to find the slope of the tangent line at the point (1,1).
After calculating the derivative and substituting x = 1, we get the slope of the tangent line. With this information, we can then write the equation of the tangent line using the point-slope form.
The final equation of the tangent line will be in the form y = mx + b, where 'm' is the slope we calculated and 'b' is the y-intercept. This equation represents the tangent line to the curve at the point (1,1).
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