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Answer :
Final answer:
The intensity of the sound with 80 dB is 10 times greater than the intensity of the sound with 50 dB. So the correct option is B.
Explanation:
The sound intensity is measured in decibels (dB). The intensity of a sound doubles for every increase of 3 dB. So, if one sound has an intensity of 50 dB and another sound has an intensity level of 80 dB, we can calculate the difference in their intensities.
For every 3 dB increase, the intensity doubles. Therefore, the difference in intensity between the two sounds is 80 dB - 50 dB = 30 dB. Since 30 dB is a multiple of 3, we know that the intensity has doubled 30/3 = 10 times.
Thus, the intensity of the sound with 80 dB is 10 times greater than the intensity of the sound with 50 dB.
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