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A sound has an intensity of 50 dB, and another sound has an intensity level of 80 dB. Which of the following is TRUE about the intensity of these two sound waves?

Let \( l_1 \) be the intensity of the 50 dB sound and \( l_2 \) be the intensity of the 80 dB sound.

A. \( l_2 = 1000 \, l_1 \)
B. \( l_2 = 0.001 \, l_1 \)
C. \( l_2 = 1.6 \, l_1 \)
D. \( l_2 = 50 \, l_1 \)
E. \( l_2 = 80 \, l_1 \)

Answer :

Final answer:

The intensity of the sound with 80 dB is 10 times greater than the intensity of the sound with 50 dB. So the correct option is B.

Explanation:

The sound intensity is measured in decibels (dB). The intensity of a sound doubles for every increase of 3 dB. So, if one sound has an intensity of 50 dB and another sound has an intensity level of 80 dB, we can calculate the difference in their intensities.

For every 3 dB increase, the intensity doubles. Therefore, the difference in intensity between the two sounds is 80 dB - 50 dB = 30 dB. Since 30 dB is a multiple of 3, we know that the intensity has doubled 30/3 = 10 times.

Thus, the intensity of the sound with 80 dB is 10 times greater than the intensity of the sound with 50 dB.

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