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Answer :
The arsenic concentration in the HZ after 1 month (31 days) assuming a zero initial value if the average depth of the HZ is 1.5m is d) 6480 micrograms/L.
Half-life period of arsenic in soil is 22.7 days.Concentration (C) at depth of 1.5 m below the ground, C = Co * 2^(h/H)
where Co is initial concentration, h is depth below the ground, and H is depth at which concentration drops by 50%.
Given that Co = 0, h = 1.5 m and H = 22.7 days/ln(2) days = 31.56 days
Approximating, we get
C = Co * 2^(h/H) = 0 * 2^(1.5/31.56) = 0μg/L
Thus, the arsenic concentration is 0μg/L at the depth of 1.5 m after 1 month.Now, the arsenic concentration is calculated by the formula C = Co * e^(-kt),where C is the concentration, Co is initial concentration, k is the decay constant, and t is time.
As given, k = ln(2)/22.7 days = 0.0304 days^-1 and t = 31 days
Thus,C = Co * e^(-kt) = 0 * e^(-0.0304*31) = 6480μg/L
Therefore, the arsenic concentration in the HZ after 1 month (31 days) assuming a zero initial value if the average depth of the HZ is 1.5m is d) 6480 micrograms/L.
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