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Answer :
Certainly! Let's solve the expression step-by-step for [tex]\( x = 1 \)[/tex].
The expression is:
[tex]\[ 6x^4 - 19x^3 - 56^2 + \frac{35}{6x} + 5 \][/tex]
Substitute [tex]\( x = 1 \)[/tex] into the expression:
1. Calculate the first term:
[tex]\( 6x^4 = 6(1)^4 = 6 \)[/tex]
2. Calculate the second term:
[tex]\(-19x^3 = -19(1)^3 = -19 \)[/tex]
3. Evaluate the constant:
[tex]\(-56^2 = -3136\)[/tex]
4. Calculate the division term:
[tex]\(\frac{35}{6x} = \frac{35}{6(1)} = \frac{35}{6} \approx 5.8333\)[/tex]
5. Calculate the last term:
[tex]\(5 = 5\)[/tex]
Now, add all the terms together:
[tex]\[ 6 + (-19) + (-3136) + 5.8333 + 5 \][/tex]
Let's calculate the total:
1. Combine the terms:
- Start by adding the terms in order:
[tex]\[ 6 - 19 = -13 \][/tex]
[tex]\[ -13 - 3136 = -3149 \][/tex]
[tex]\[ -3149 + 5.8333 = -3143.1667 \][/tex]
[tex]\[ -3143.1667 + 5 = -3138.1667 \][/tex]
Therefore, when [tex]\( x = 1 \)[/tex], the value of the expression is approximately [tex]\(-3138.167\)[/tex].
The expression is:
[tex]\[ 6x^4 - 19x^3 - 56^2 + \frac{35}{6x} + 5 \][/tex]
Substitute [tex]\( x = 1 \)[/tex] into the expression:
1. Calculate the first term:
[tex]\( 6x^4 = 6(1)^4 = 6 \)[/tex]
2. Calculate the second term:
[tex]\(-19x^3 = -19(1)^3 = -19 \)[/tex]
3. Evaluate the constant:
[tex]\(-56^2 = -3136\)[/tex]
4. Calculate the division term:
[tex]\(\frac{35}{6x} = \frac{35}{6(1)} = \frac{35}{6} \approx 5.8333\)[/tex]
5. Calculate the last term:
[tex]\(5 = 5\)[/tex]
Now, add all the terms together:
[tex]\[ 6 + (-19) + (-3136) + 5.8333 + 5 \][/tex]
Let's calculate the total:
1. Combine the terms:
- Start by adding the terms in order:
[tex]\[ 6 - 19 = -13 \][/tex]
[tex]\[ -13 - 3136 = -3149 \][/tex]
[tex]\[ -3149 + 5.8333 = -3143.1667 \][/tex]
[tex]\[ -3143.1667 + 5 = -3138.1667 \][/tex]
Therefore, when [tex]\( x = 1 \)[/tex], the value of the expression is approximately [tex]\(-3138.167\)[/tex].
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