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Answer :
Final answer:
The 16th term of the given arithmetic progression (AP) is -82, and 100 cannot be a term of this AP because all terms are decreasing and are less than 100.
Explanation:
The given arithmetic progression (AP) starts at -7 and has a common difference of -5 (that is, each term is 5 less than the previous term). To answer your first question, we can use the formula for the nth term of an AP, which is a + (n - 1) * d, where 'a' is the first term, 'n' is the term number, and 'd' is the common difference.
For -82 = -7 + (n - 1) * -5, solving this equation gives n = 16. So, the 16th term of the AP is -82.
As for whether 100 is a term in this progression, since the common difference is negative (meaning each term is less than the previous one), the terms will continue to decrease without limit. Therefore, 100 cannot be a term. The reason is that 100 is greater than any term in the progression.
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