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A non-ideal 12 V battery is connected in a circuit with a single resistor of resistance 6 Ω. A voltmeter connected across the resistor reads 9 V. What is the internal resistance of the battery?

Answer :

Final answer:

To calculate the internal resistance of a nonideal battery in a circuit, use the formula r = (AVideal - V)/(I) where AVideal is the ideal battery voltage, V is the voltage across the resistor, and I is the current. In this specific scenario, with a 12 V battery, a 6 ohm resistor, and a 9 V voltmeter reading, the internal resistance is 0.33 ohms.

Explanation:

In this scenario, we can use the concept of internal resistance to determine the resistance within the nonideal battery. The formula to calculate the internal resistance (r) of the battery is given by: r = (AVideal - V)/(I), where AVideal is the ideal voltage of the battery, V is the voltage across the resistor, and I is the current flowing through the circuit.

Given that the battery is 12 V, the resistor has a resistance of 6 ohms, and the voltmeter reads 9 V, we can calculate the internal resistance using the formula mentioned above. Plugging in the values, we get r = (12 - 9)/9 = 1/3 = 0.33 ohms.

Therefore, the internal resistance of the battery is 0.33 ohms.

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