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Answer :
The elevator rises at a distance of 8.38 meters in 2 seconds, assuming it starts at rest.
Given:
Mass of the elevator: 3000 kg
Upward tension in the cable: 42000 N
Time: 2 seconds
Initial velocity: 0 m/s
Using Newton's second law:
Force = mass × acceleration
Tension - Weight = mass × acceleration
Weight (mg) = 3000 × 9.81
Weight (mg) = 29430 N
The acceleration is:
Acceleration (a) = (Tension - Weight) / mass
Acceleration (a) = (42000 - 29430) / 3000
Acceleration (a) = 4.19 m/s²
The kinematic equation for displacement:
Distance = Initial velocity × Time + 0.5 × Acceleration × Time²
Distance = (0) × (2 ) + 0.5 × (4.19 ) × (2)²
Distance = 0 + 0.5 × 4.19 × 4²
Distance = 0 + 8.38 m
So, the elevator rises at a distance of approximately 8.38 meters in 2 seconds, assuming it starts at rest.
To know more about displacement and distance:
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Rewritten by : Barada
Answer: 8.4 m
Explanation: I have no idea how I came to this conclusion but it is right
