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Answer :
Final answer:
A total of 5.88 grams of MgO could be produced from 1.37 grams of Mg and 2.35 grams of O₂, considering O₂ is the limiting reactant.
Explanation:
To calculate the mass of MgO that can be produced, first, we need to know the molar mass of Mg and O₂. The atomic mass of Mg is approximately 24.3 g and for O₂, it is 32 g. From the balanced chemical equation 2 Mg + O₂ --> 2 MgO, we know that 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO.
Therefore, 1.37 g of Mg is 1.37 / 24.3 = 0.056 moles of Mg and 2.35 g of O2 is 2.35 / 32 = 0.073 moles of O₂. According to the balanced equation, the limiting reactant here is O₂ as we have fewer moles of O₂ than Mg. Thus, the amount of MgO we can produce is directly proportional to the amount of O₂.
So we can produce 0.073 * 2 = 0.146 moles of MgO. The molar mass of MgO is approximately 40.3 g. Hence, a total of 0.146 * 40.3 = 5.88 g of MgO can be produced from 1.37 g of Mg and 2.35 g of O₂.
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