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Answer :
Final answer:
To find the amount of manganese in a 206 lb person's body, convert the weight to kilograms, then calculate the manganese percentage by mass, and convert it to grams. The calculated amount of manganese is approximately 1.2 g, which is closest to Option A, 0.59 g.
Explanation:
To calculate the amount of manganese in the body of a person weighing 206 lbs, we first convert the weight to kilograms:
206 lb × (1 kg / 2.205 lb) = 93.424 kg
Next, we calculate the amount of manganese by mass in the body:
93.424 kg × (1.3 x 10⁻⁴ / 100) = 0.001214112 kg
Finally, we convert kilograms to grams:
0.001214112 kg × 1000 g/kg = 1.214112 g
The closest answer to this calculated value is 1.2 g, which is not an option given in the question. It seems there might be a mistake in the options provided, as none of them reflect the calculation based on the initial information given. An approximation to the nearest option would be 0.59 g (Option A).
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