High School

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A sequence is defined by the recursive function [tex]f(n+1) = \frac{1}{3} f(n)[/tex]. If [tex]f(3) = 9[/tex], what is [tex]f(1)[/tex]?

A. 1
B. 3
C. 27
D. 81

Answer :

Let's solve the problem step by step:

1. Understand the recursive function: We are given that the sequence is defined by the recursive relation [tex]\( f(n+1) = \frac{1}{3} f(n) \)[/tex]. This means each term in the sequence is one third of the previous term.

2. Use the given value: We are told that [tex]\( f(3) = 9 \)[/tex]. Based on the recursive relation, we can calculate the earlier terms in the sequence by working backwards.

3. Calculate [tex]\( f(2) \)[/tex]: Since [tex]\( f(3) = \frac{1}{3} f(2) \)[/tex], we can find [tex]\( f(2) \)[/tex] by multiplying [tex]\( f(3) \)[/tex] by 3:
[tex]\[
f(2) = 3 \times f(3) = 3 \times 9 = 27
\][/tex]

4. Calculate [tex]\( f(1) \)[/tex]: Similarly, since [tex]\( f(2) = \frac{1}{3} f(1) \)[/tex], we find [tex]\( f(1) \)[/tex] by multiplying [tex]\( f(2) \)[/tex] by 3:
[tex]\[
f(1) = 3 \times f(2) = 3 \times 27 = 81
\][/tex]

5. Conclusion: Therefore, based on these calculations, the value of [tex]\( f(1) \)[/tex] is [tex]\( 81 \)[/tex].

The answer is [tex]\( \boxed{81} \)[/tex].

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