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Answer :
When the current in an inductor is increasing at a uniform rate of 8.00 A/s the voltage across the inductor is 4.00 V. 0.500 H is the self-inductance of the inductor.
[tex]\frac{dI}{dt} = 8A/s , V= 4V\\[/tex]
V= ∠[tex]\frac{dI}{dt}[/tex]
so, ∠ [tex]\frac{v}{\frac{dI}{dt} } = \frac{4}{8} = 0.5 H[/tex]
The current in an inductor can not change presently because it implies an horizonless voltage will live, which is not going to be. This disinclination to change is because of the energy stored in the inductor's glamorous field. The current in an inductor doesn't( will not) change presently.
What happens to current in an inductor?
As an inductor stores more energy, its current position increases, while its voltage drop decreases. Note that this is precisely the contrary of capacitor geste , where the storehouse of energy results in an increased voltage across the element!
To know more about Current in an Indicator, visit: brainly.com/question/14041701
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