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Answer :
Final answer:
The decay of neon-17 (^17Ne) via beta-plus decay (ß+ decay) results in the formation of oxygen-17 (^17O), along with the emission of a positron and a neutrino.
Explanation:
The student is dealing with a nuclear chemistry concept involving beta-plus decay (ß+ decay). In this process, a proton in the nucleus is converted into a neutron and a positron (the ß+ particle) is emitted alongside a neutrino (ve). Referring to the periodic table information provided, when a neon-17 atom undergoes ß+ decay, it will transform into an isotope with one less proton, which is oxygen-17 (17O), because neon (Ne) has the atomic number 10 and oxygen (O) has the atomic number 9, which is one less. Hence, the correct equation for the decay of 17Ne is 17Ne → 17O + ß+ + ve.
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