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Answer :
Final answer:
By substituting t = 4 into the given equation P=3t^2+13, we find that Option b) P(4) = 61 feet is correct. This means, the rocket is 61 feet away from the satellite after 4 seconds of acceleration.
Explanation:
To determine the distance between the rocket and the satellite after 4 seconds of acceleration, we substitute t = 4 into the given equation P=3t^2+13. So, P = 3*(4)^2 + 13 = 48 + 13 = 61 feet. This implies, Option b) P(4) = 61 feet is correct, denoting that the rocket is 61 feet away from the satellite after 4 seconds of acceleration. Remember that in such problems, t represents time elapsed and P is usually the position or distance from a reference point, here being the satellite.
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