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Answer :
The volume of 6.00 M NaOH required to obtain 2.50 moles of the solute is 0.417 L (or 417 mL). the 6.00 M NaOH solution would be required to obtain 2.50 moles of the solute.
To calculate the volume of a solution, we can use the formula:
Volume (L) = Moles ÷ Concentration (M)
Given that the moles of the solute (NaOH) is 2.50 and the concentration of the solution is 6.00 M, we can substitute these values into the formula:
Volume (L) = 2.50 moles ÷ 6.00 M = 0.417 L
This means that 0.417 liters (or 417 mL) of the 6.00 M NaOH solution would be required to obtain 2.50 moles of the solute.
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