High School

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Tory has a mass of 40 kg. She sleds down a hill that has a slope of 25°. What is the component of her weight along her direction of motion?

A. 392 N
B. 355 N
C. 166 N
D. 198 N

Answer :

Final answer:

The component of Tory's weight along the direction of motion down a hill with a 25° slope is found using the formula W|| = mg sin(θ). With a mass of 40 kg, the component of weight parallel to the slope is 166 N, making the correct answer C. 166 N.Therefore the correct option is C.

Explanation:

The student is asking about the component of weight along the direction of motion when Tory, with a mass of 40 kg, sleds down a hill with a slope of 25°. This is a physics problem related to forces on an incline.

The formula to find the component of weight parallel to the slope is W|| = w sin(θ) = mg sin(θ), where w is the weight, m is the mass, g is the acceleration due to gravity (9.8 m/s2), and θ is the angle of the slope.

Therefore, the component of Tory's weight along her direction of motion is calculated as follows:

W|| = (40 kg)(9.8 m/s2) sin(25°) = 392 N sin(25°) = 166 N

The correct answer to the question is C. 166 N.

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