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What is the molarity of a solution made by dissolving 39.4 g of lithium chloride in enough water to make 1.59 L of solution?

Answer :

molar mass LiCl = 42.394 g/mol

number of moles solute:

n = mass of solute / molar mass

n = 39.4 / 42.394

n = 0.929 moles

Therefore:

Molarity = number of moles / volume ( L )

M = 0.929 / 1.59

M = 0.584 mol/L

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Rewritten by : Barada

Final answer:

The molarity of a solution made by dissolving 39.4 g of lithium chloride in 1.59 L of water is calculated to be 0.584 M, by first determining the number of moles of LiCl and then applying the formula for molarity.

Explanation:

To calculate the molarity of a solution made by dissolving 39.4 g of lithium chloride (LiCl) in enough water to make 1.59 L of solution, we need to follow these steps:

Calculate the number of moles of LiCl. The molar mass of LiCl is 42.39 g/mol. The number of moles is calculated as mass (g) ÷ molar mass (g/mol). So, for 39.4 g of LiCl, the calculation is 39.4 g ÷ 42.39 g/mol = 0.929 moles of LiCl.

Convert the volume of solution from liters to liters, which is already given as 1.59 L.

Calculate the molarity. Molarity is defined as moles of solute ÷ liters of solution. Therefore, the molarity is 0.929 moles ÷ 1.59 L = 0.584 M.

The molarity of the solution is 0.584 M.