High School

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A cabinet weighing 100 N is placed on a floor. The amount of contact area between the cabinet and the floor is [tex]0.5 \, m^2[/tex].

How much pressure does the cabinet exert on the floor?

A. 0.005 Pa
B. 50 Pa
C. 200 Pa
D. 100.5 Pa

Answer :

To determine the pressure exerted by the cabinet on the floor, we use the formula:

[tex]\[ P = \frac{F}{A} \][/tex]

where:
- [tex]\( P \)[/tex] is the pressure,
- [tex]\( F \)[/tex] is the force (or weight in this context),
- [tex]\( A \)[/tex] is the contact area.

Given:
- The weight [tex]\( F \)[/tex] of the cabinet is 100 Newtons (N),
- The contact area [tex]\( A \)[/tex] is [tex]\( 0.5 \, \text{m}^2 \)[/tex].

Now, plug in the values:

[tex]\[ P = \frac{100 \, \text{N}}{0.5 \, \text{m}^2} \][/tex]

[tex]\[ P = 200 \, \text{Pa} \][/tex]

Therefore, the pressure exerted by the cabinet on the floor is [tex]\( 200 \, \text{Pa} \)[/tex].

Among the choices given:
- 0.005 Pa
- 50 Pa
- 200 Pa
- 100.5 Pa

The correct answer is [tex]\( 200 \, \text{Pa} \)[/tex].

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Rewritten by : Barada