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At a pizza-eating competition, Sean ate three more than twice as many slices as the runner-up. If Sean ate 11 slices, how many slices did the runner-up eat?

Answer :

Final answer:

By creating and solving an algebraic equation, it was determined that the runner-up in the pizza eating competition ate 4 slices of pizza.

Explanation:

The question involves solving a simple algebraic equation to find the number of pizza slices eaten by the runner-up in a pizza eating competition.

Let's denote the number of slices the runner-up ate as x. According to the problem, Sean ate three more than twice as many slices as the runner-up. We can write this as an equation: 2x + 3 = 11.

To find the value of x, we need to solve the equation:

  1. Subtract 3 from both sides: 2x = 11 - 3
  2. Simplify the right side: 2x = 8
  3. Divide both sides by 2 to solve for x: x = 4

Therefore, the runner-up ate 4 slices of pizza.

Learn more about solving an equation here:

https://brainly.com/question/17595716

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