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Answer :
Final answer:
The equivalent capacitance of four 40 F capacitors connected in series is 10 F (answer c).
Explanation:
The student's question asks for the equivalent capacitance when four capacitors, each with a capacitance of 40 F, are connected in series. To find the equivalent capacitance of capacitors in series, the reciprocal principle is used, which is represented by the formula:
1/Cs = 1/C1 + 1/C2 + 1/C3 + 1/C4
For capacitors of equal value, you can simplify this to:
1/Cs = 4/C
where C is the capacitance of each individual capacitor. Solving for Cs, the equivalent series capacitance, we get:
Cs = C/4
Giving us:
Cs = 40 F / 4 = 10 F
The correct answer to the student's question is c) 10 F, which is the series equivalent capacitance of the configuration.
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