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Answer :
To solve these number pattern questions, we need to identify the pattern or rule that applies to each sequence of numbers and then find the missing term based on that pattern.
a. 18, 15, 1, 3, 5, 7
This sequence alternates between subtracting 3 and adding a number that increases by 2 each time (from a starting point of 1). So, starting from 18, we subtract 3 to get 15, then add 1 to get 16 (not shown), subtract 3 again to get 13, and continue by adding 3 to get 1, then 3, 5, 7.
The correction should be that 1 is incorrect here. The correct pattern should start with 18, subtract 3 to get 15, then subtract another 3 to 12, instead of 1.
b. 21, 18, 15, 12
This sequence is decreasing by 3 each time. So, the missing term follows this rule:
21 - 3 = 18, 18 - 3 = 15, 15 - 3 = 12. Hence, if we continue, we get 12 - 3 = 9.
c. 173, 170, 165, 160
This sequence is decreasing with a pattern: start by subtracting 3, then 5, then 5 again. So, 173 - 3 = 170, 170 - 5 = 165, 165 - 5 = 160. Next, 160 should decrease by 10 (following the pattern of decreasing subtractions that increase in value).
d. 336, 302, 305, 354
This pattern alternates between an unknown consistent change. This looks like subtract 34, add 3, and add 49. We can assume we missed an alternate subtraction to continue the series, like 354 - 34.
e. 3, 5 \frac{1}{4}, 4, \frac{5}{5}
This sequence is not consistent, but if adjusted for known symbols used in sequences, which seems to show increments in fractional parts not clearly specified. Correct structure may be needed here.
f. 10.8, 10.6, 10.4, 10.2
Each term is decreasing by 0.2. Therefore, the pattern is subtract 0.2 each time:
10.8 - 0.2 = 10.6, 10.6 - 0.2 = 10.4, and so forth.
g. 7 \frac{1}{2}, 8, 8 \frac{1}{2}, 9
This sequence increases by [tex]\frac{1}{2}[/tex]. So, starting with 7 [tex]\frac{1}{2}[/tex], adding [tex]\frac{1}{2}[/tex] results in 8, then 8 [tex]\frac{1}{2}[/tex], and finally 9 results in 9 [tex]\frac{1}{2}[/tex].
h. 2, 4, 8, 16
This sequence is multiplying by 2 each time. So, the verse sequence is 2, 4, 8, 16, and the continuation is 16 \times 2 = 32.
i. 125, 25, 5, 1
This sequence is divided by 5 each time. So, starting from 125, [tex]\frac{125}{5} = 25[/tex], [tex]\frac{25}{5} = 5[/tex], [tex]\frac{5}{5} = 1[/tex].
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