High School

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Shown below are two charges with opposite polarity, but their charge magnitudes are equal. They are 186 cm apart. There is a point in between them where the net potential is zero. How far is that point from charge B?

Answer :

Final answer:

The point of zero net potential is approximately 62 cm from charge B when two charges with opposite polarity but equal magnitudes are placed 186 cm apart.

Explanation:

The student is essentially asking you to find the point between two equal but oppositely charged objects where the electric potential is zero, in this case, specifically from charge B. This concept relates to Coulomb's law and the principles of electric potential in physics. The net potential at a point due to several charges is equal to the algebraic sum of the potentials from the individual charges.

To solve it, let's denote the positive charge as A and the negative charge as B. Since they have the same magnitude and A is positive, where the potential (V) is 0 will be closer to B. If 'd' represents the distance from B, the equation to apply here would be -kQ/d = kQ/(186-d), because the electric potential is the sum of potential contributions from all charges, and it is zero here.

When you solve the above equation, you'll find that d ≈ 62 cm. Therefore, the point of zero net potential is about 62 cm from charge B.

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