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Arrange the following elements in increasing atomic size:

A. Rb, Sb, I, Sn, Sr

B. I, Rb, Sb, Sr, Sn

C. Sn, Sr, Sb, Rb, I

D. I, Rb, Sr, Sb, Sn

Answer :

Final answer:

The correct answer is C. Sn, Sr, Sb, Rb, I. To arrange Rb, Sb, I, Sn, and Sr in increasing atomic size, one should consider their positions on the periodic table, where atomic size increases down a group and decreases across a period.

Explanation:

To determine the order of increasing atomic size for the elements Rb, Sb, I, Sn, and Sr, we need to consider their positions on the periodic table. Atomic size tends to increase as we move down a group and decreases as we move across a period from left to right. Given the elements provided:


  • Iodine (I) is in period 5, group 17.

  • Rubidium (Rb) is in period 5, group 1.

  • Strontium (Sr) is in period 5, group 2.

  • Tin (Sn) is in period 5, group 14.

  • Antimony (Sb) is in period 5, group 15.

Since Rb is in group 1 and Sr is in group 2, they will have larger atomic sizes compared to Sn, Sb, and I. The correct order from smallest to largest atomic size is:


  3. I (Iodine)

  6. Sn (Tin)

  9. Sb (Antimony)

  12. Sr (Strontium)

  15. Rb (Rubidium)

Therefore, the correct answer is C. Sn, Sr, Sb, Rb, I, arranged in order of increasing atomic size.

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