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Answer :
16 bottles of wine is filled by releasing of argon from canister.
When is the canister's argon released?
The argon expands to fill the wine bottle when it is let go from the canister. At a pressure of 1.20 atm and a temperature of 295 K, how many 750.0-mL wine bottles can be purged with the argon in the canister?
A wine bottle's size is how big.
The typical 750 ml bottle is 25.4 ounces (the metric for beverage alcohol on a wine label is always milliliters). That is roughly 1.5 pints or roughly three-quarters of a quart for those who do not use the metric system.
V = nRT/P from the ideal gas law. n = .65, r = .082, T = 297, and P = 1.26. Plugging those values in gives us a volume of 12.56 L. To find out how many bottles we need, we can do 15.83L/.75L to give us about 16 bottles of wine.
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To calculate how many 750.0-ml wine bottles can be purged with argon from a canister, the ideal gas law equation can be used; however, the amount of argon in the canister is needed to find the answer.
The question deals with the number of 750.0-ml wine bottles that can be purged with argon from a canister at a pressure of 1.26 atm and a temperature of 297 K. To solve this, we could use the ideal gas law equation to find the volume of argon in the canister:
PV = nRT
Where:
P is the pressure of the gas (1.26 atm),
V is the volume of the gas,
n refers to the number of moles of the gas,
R is the ideal gas constant (0.0821 L atm/mol K),
T is the temperature in Kelvin (297 K).
Once we calculate the volume 'V' of argon in the canister, we can divide this value by 750 ml to get the number of wine bottles that can be purged. This process necessitates the amount of argon, which the question has omitted; thus, an additional piece of information is required to solve it.
