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Answer :
Final answer:
The student's question involves the calculation of distance between the plates of a parallel-plate capacitor, given its charge, potential difference and plate area. Through two phases of calculation using the fundamental formula for capacitance and the formula for capacitance of a dielectric-filled, parallel-plate capacitor, we find that the required separation of the plates is approximately 73.3 mm.
Explanation:
An ideal air-filled parallel-plate capacitor stores charge using the potential difference between the plates. The equation that represents this relationship is given by C=Q/V. In this case, the charge Q is 277.9 pC (which is equal to 277.9e-12 C when converted to Coulombs), and the potential difference V is 36.3V. Solving for the capacitance C gives us a value of approximately 7.66e-12 F.
Next, we can find the dielectric constant (K) for air which is approximately 1. The formula for capacitance for a parallel-plate capacitor filled with a dielectric material is C = ε0 * K * (A/d), where ε0 is the permittivity of free space, A is the area of one plate, and d is the separation between the plates. Substituting the values we have, and solving for d, we find that the separation between the plates is approximately 73.3 mm.
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