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You begin with a block of 99.9 g of aluminum in the solid phase at 25.0°C and heat it until the block reaches 660.0°C. Determine the amount of energy (in kJ) required to accomplish this.

Answer :

Final answer:

The amount of energy needed to heat a 99.9g aluminum block from 25.0°C to 660.0°C is approximately 56.65 kilojoules, as calculated using the heat transfer equation and the specific heat capacity of aluminum.

Explanation:

The question is asking for the amount of energy required to heat a block of aluminum from 25.0 Celsius to 660.0 Celsius. The necessary calculation uses the equation for heat transfer Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity of aluminum, and ΔT is the change in temperature.

Given that the mass of aluminum is 99.9 g, the specific heat capacity of aluminum is 0.897 J/g°C (from Table 9.1), the initial temperature is 25.0°C and the final temperature is 660.0°C, we can substitute these values into the equation.

This gives Q = 99.9 g * 0.897 J/g°C * (660-25)°C = 56,649.255 joules. Since the question asked for the answer in kilojoules, we need to convert from joules to kilojoules by dividing by 1,000: 56.65 kJ.

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