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Answer :
The E string vibrating faster than the G string on a violin will result in a sound with a higher frequency and shorter wavelength.
If a violin string E vibrates faster than another violin string G when bowed, then the string E will produce a sound with a higher frequency. The frequency of the sound wave in the air is identical to the vibration frequency of the string itself. This is because the vibrating string pushes air molecules, creating sound waves that propagate in the surrounding environment.
The speed of sound in the air for both strings is the same, but since string E vibrates faster, its sound frequency will be higher. Additionally, because the wavelength (lembda) of a sound wave is related to its speed (v) and frequency (f) by the equation v =f× lembd , the sound wave from the faster vibrating E string will have a shorter wavelength compared to the slower vibrating G string.
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