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Answer :
Final answer:
Mass of C = moles of C x molar mass of C = 0.15 moles x 98.5 g/mol = 14.775 grams
Explanation:
Given:
- Mass of reactant A = 15.0 g
- Molar mass of reactant A (FW) = 102 g/mol
- Volume of reactant B = 50.0 mL
- Concentration of reactant B = 3.0 M
- Molar mass of reactant B (FW) = 52.3 g/mol
- Molar mass of product C (FW) = 98.5 g/mol
First, calculate the moles of reactant A:
Moles of A = mass of A / molar mass of A = 15.0 g / 102 g/mol = 0.147 moles
Then, calculate the moles of reactant B:
Moles of B = concentration of B x volume of B = 3.0 M x 0.050 L = 0.15 moles
Since reactant B has a higher number of moles (0.15 moles) than reactant A (0.147 moles), B is the limiting reactant. Therefore, the moles of C produced will be equal to the moles of B.
Finally, convert the moles of C to grams:
Mass of C = moles of C x molar mass of C = 0.15 moles x 98.5 g/mol = 14.775 grams
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