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Answer :
Answer:
Cost of each apple cake is $4 and Cost of each Lemon merinque cake is $14.
Step-by-step explanation:
Let the cost of each apple cakes be 'x'.
Let the cost of each lemon merinque cake be 'y'.
Now Given:
Castel sold 6 apple cakes and 4 lemon merinque cakes for a total of $ 80.
So we can say that;
6 times cost of each apple cakes plus 4 times cost of each lemon merinque cake is equal to $ 80.
framing in equation form we get;
[tex]6x+4y=80[/tex] ⇒ Equation 1
Also Given:
Gabriella sold 6 apple cakes and 5 lemon merinque cakes for a total of $ 94.
6 times cost of each apple cakes plus 5 times cost of each lemon merinque cake is equal to $ 94.
framing in equation form we get;
[tex]6x+5y=94[/tex] ⇒ Equation 2
Now subtracting equation 1 from equation 2 we get;
[tex]6x+5y-(6x+4y)=94-80\\\\6x+5y-6x-4y=14\\\\y=\$14[/tex]
Substituting the value of y in equation 1 we get;
[tex]6x+4y =80\\\\6x+4\times14=80\\\\6x+56=80\\\\6x=80-56\\\\6x=24[/tex]
Dividing both side by 6 we get;
[tex]\frac{6x}{6}=\frac{24}{6}\\\\x=\$4[/tex]
Hence Cost of each apple cake is $4 and Cost of each Lemon merinque cake is $14.
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Rewritten by : Barada
The apple cake costs $9, and the lemon meringue cake costs $14.
Let's solve this system of equations:
6a + 4m = 80
6a + 5m = 94
Subtracting the first equation from the second, we get: m = 14. Then, by substituting m into the first equation, a = 9. Thus, each apple cake costs $9, and each lemon meringue cake costs $14.