High School

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Determine the maximum weight of the flowerpot that can be supported without exceeding a cable tension of 71.5 lb in either cable AB or AC.

A. 35.75 lb
B. 71.5 lb
C. 143 lb
D. 107.25 lb

Answer :

Final answer:

The maximum weight of the flowerpot that can be supported by two cables without exceeding the cable tension of 71.5 lb in either cable is 143 lb. Therefore the correct answer is c).

Explanation:

To determine the maximum weight of the flowerpot that can be supported without exceeding a cable tension of 71.5 lb in either cable, we need to consider that the tension in each cable will be equal if the flowerpot hangs symmetrically.

Since the question specifies a maximum tension of 71.5 lb in either cable, the total weight supported by both cables together is 71.5 lb + 71.5 lb, which equals to 143 lb. Therefore, for each cable to not exceed the 71.5 lb tension limit, the maximum weight of the flowerpot can be 143 lb, assuming the weight is evenly distributed between the two cables.

There are a variety of formulas to use for finding someone's one rep max. The most popular formula is the formula from Matt Brzycki, which is weight divided by ( 1.0278 – 0.0278 × reps ). Epley's formula is the weight multiplied by (1 + 0.0333 × reps). Lander's formula is (100 × weight ) / (101.3 – 2.67123 × reps).

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