A toy rocket is launched from the ground with a speed of 18 m/s. It travels straight up, comes back down, and hits the ground. How long is it in the air?

Question

15-04-2024
Physics

High School

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A toy rocket is launched from the ground with a speed of 18 m/s. It travels straight up, comes back down, and hits the ground. How long is it in the air?

Answer :

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JulieRobin JulieRobin · Answer 1 · 2024-09-24T15:10:29-04:00

Final answer:

The toy rocket is in the air for twice the time it takes to reach its maximum height, when it comes back down and hits the ground.

Explanation:

The time the toy rocket is in the air can be determined using the equations of motion in vertical motion. The rocket is launched upwards with an initial speed of 18 m/s and it comes back to the ground. When an object is thrown upwards and lands at the same height, the time in the air is given by twice the time taken to reach the maximum height.

The vertical motion can be divided into two parts: the upward motion and the downward motion. The upward motion is symmetrical to the downward motion, and both have the same time of flight. Therefore, the time the rocket is in the air is twice the time taken to reach the maximum height.

We can calculate the time taken to reach the maximum height using the equation: time = initial velocity/acceleration due to gravity. Using the given value of initial velocity as 18 m/s and considering the acceleration due to gravity as 9.8 m/s², we can calculate the time taken. Doubling this value will give us the total time the rocket is in the air.

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