We appreciate your visit to Crystal is loading a wheelbarrow with bricks that each have the same weight so she can build a fire pit in her backyard When the. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The initial value of 145 pounds represents the combined weight of the wheelbarrow and the 40 bricks it contains. When Crystal added more bricks, the total weight increased, allowing us to calculate each brick's weight.
Explanation:
In this scenario, the initial value of 145 pounds represents the total weight of the wheelbarrow when it contains 40 bricks. It is the weight of the wheelbarrow plus the weight of the bricks it contains. The wheelbarrow itself also has its own weight which is part of the initial value. However, since we don't have the standalone weight of the wheelbarrow, we interpret the initial value as the total weight with the 40 bricks inside.
When Crystal added 5 more bricks, the total weight increased to 160 pounds. Therefore, the difference, 160 - 145 = 15 pounds, can be attributed to the weight of the 5 bricks. Hence, each brick weighs 15/5 = 3 pounds.
Learn more about Weight Calculation here:
https://brainly.com/question/31409659
#SPJ11
Thanks for taking the time to read Crystal is loading a wheelbarrow with bricks that each have the same weight so she can build a fire pit in her backyard When the. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada