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Answer :
Final answer:
The energy released in the fission reaction is approximately 2.7918 ⨯ 10-11 joules.
Explanation:
In this fission reaction, uranium-235 (235U) absorbs a neutron (n) and splits into barium-143 (143Ba), krypton-90 (90Kr), and three neutrons (3n). The energy released in the reaction can be calculated by determining the mass difference between the reactants and the products and multiplying it by the speed of light squared [tex](c^2)[/tex].
First, let's calculate the total mass of the reactants (235U + n):
- Mass of uranium-235 (235U): 390.29 ⨯ 10-27 kg
- Mass of a neutron (n): 1.6749 ⨯ 10-27 kg
Total mass of reactants = Mass of uranium-235 + Mass of neutron = 390.29 ⨯ 10-27 kg + 1.6749 ⨯ 10-27 kg = 391.9649 ⨯ 10-27 kg
Next, let's calculate the total mass of the products (143Ba + 90Kr + 3n):
- Mass of barium-143 (143Ba): 237.32 ⨯ 10-27 kg
- Mass of krypton-90 (90Kr): 149.31 ⨯ 10-27 kg
- Mass of three neutrons (3n): 3 ⨯ 1.6749 ⨯ 10-27 kg = 5.0247 ⨯ 10-27 kg
Total mass of products = Mass of barium-143 + Mass of krypton-90 + Mass of three neutrons = 237.32 ⨯ 10-27 kg + 149.31 ⨯ 10-27 kg + 5.0247 ⨯ 10-27 kg = 391.6547 ⨯ 10-27 kg
The mass difference between the reactants and the products is:
Mass difference = Total mass of reactants - Total mass of products = 391.9649 ⨯ 10-27 kg - 391.6547 ⨯ 10-27 kg = 0.3102 ⨯ 10-27 kg
Finally, we can calculate the energy released using Einstein's equation E=mc^2:
Energy released = Mass difference ⨯ (speed of light[tex])^2[/tex] = 0.3102 ⨯ 10-27 kg ⨯ (3.00 ⨯ 108 m/s[tex])^2[/tex] = 2.7918 ⨯ 10-11 J
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